-12x^2+60x+12=0

Solution for -12x^2+60x+12=0 equation:

-12x^2+60x+12=0

a = -12; b = 60; c = +12;
Δ = b2-4ac
Δ = 602-4·(-12)·12
Δ = 4176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4176}=\sqrt{144*29}=\sqrt{144}*\sqrt{29}=12\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-12\sqrt{29}}{2*-12}=\frac{-60-12\sqrt{29}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+12\sqrt{29}}{2*-12}=\frac{-60+12\sqrt{29}}{-24}
$